Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 6 - Section 6.8 - Modeling Using Variation - Exercise Set - Page 487: 5

Answer

$\frac{5}{6}.$

Work Step by Step

The equation here is $y=\frac{kx}{z^2}$. Thus $20=\frac{50k}{5^2}\\20=2k\\k=10$. Hence $y=\frac{10x}{z^2}=\frac{10\cdot3}{6^2}=\frac{30}{36}=\frac{5}{6}.$
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