Answer
$\frac{7}{4}.$
Work Step by Step
The equation here is $a=\frac{kb}{c^2}$. Thus $7=\frac{9k}{6^2}\\252=9k\\k=28$.
Hence $a=\frac{28b}{c^2}=\frac{28\cdot4}{8^2}=\frac{112}{64}=\frac{7}{4}.$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 6 - Section 6.8 - Modeling Using Variation - Exercise Set - Page 487: 6
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