Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 6 - Section 6.7 - Formulas and Applications of Rational Equations - Exercise Set - Page 477: 53

Answer

$10$ consecutive hits

Work Step by Step

The new number of hits is $35+x$ (add x to the numerator), out of $140+x$ outings with the bat (add x to the denominator). $\displaystyle \frac{35+x}{140+x}=0.30$ $\displaystyle \frac{35+x}{140+x}=\frac{3}{10}\qquad $... $/\times 10(140+x)$ $10(35+x)=3(140+x)$ $ 350+10x=420+3x\qquad$ ... add $-350-3x$ $7x=70$ $x=10$
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