Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 6 - Section 6.7 - Formulas and Applications of Rational Equations - Exercise Set - Page 477: 49

Answer

$3$

Work Step by Step

$\left[\begin{array}{lll} \text{What number} & \rightarrow & x...\\\\ \text{multiplied by the numerator} & & \\ \text{and added to the denominator of 4/5} & \rightarrow & \dfrac{4x}{x+5} \\ \\ \text{... equivalent to 3/2} & \rightarrow & =3/2 \end{array}\right]$ $\displaystyle \frac{4x}{x+5}=\frac{3}{2}\qquad/...\times 2(x+5)$ $4x(2)=3(x+5)$ $8x=3x+15\qquad/...-3x$ $5x=15\qquad/...\div 5$ $x=3$
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