Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 6 - Section 6.7 - Formulas and Applications of Rational Equations - Exercise Set - Page 477: 50


$-\displaystyle \frac{132}{33}$

Work Step by Step

$\left[\begin{array}{lll} \text{What number} & \rightarrow & x...\\\\ \text{multiplied by the numerator and } & & \\ \text{subtracted from the denominator of }\dfrac{9}{11} & \rightarrow & \dfrac{9x}{11-x} \\ \\ \text{makes fraction... equivalent to }-\dfrac{12}{5} & \rightarrow & =-\dfrac{12}{5} \end{array}\right]$ $\displaystyle \frac{9x}{11-x}=-\frac{12}{5}\qquad/...\times 5(11-x)$ $9x(5)=-12(11-x)$ $45x=-132+12x\qquad/...-12x$ $33x=-132\qquad/...\div 33$ $x=-\displaystyle \frac{132}{33}$
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