Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 6 - Section 6.4 - Division of Polynomials - Exercise Set - Page 444: 8


$-9x^{3}+\displaystyle \frac{9}{2}x^{2}-10x+5$

Work Step by Step

Using the property: $\displaystyle \quad\frac{A+B}{C}=\frac{A}{C}+\frac{B}{C},$ $\displaystyle \frac{18x^{7}-9x^{6}+20x^{5}-10x^{4}}{-2x^{4}}=\frac{18x^{7}}{-2x^{4}}-\frac{9x^{6}}{-2x^{4}}+\frac{20x^{5}}{-2x^{4}}-\frac{10x^{4}}{-2x^{4}}$ = $-9x^{3}+\displaystyle \frac{9}{2}x^{2}-10x+5$
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