Answer
$-9x^{3}+\displaystyle \frac{9}{2}x^{2}-10x+5$
Work Step by Step
Using the property: $\displaystyle \quad\frac{A+B}{C}=\frac{A}{C}+\frac{B}{C},$
$\displaystyle \frac{18x^{7}-9x^{6}+20x^{5}-10x^{4}}{-2x^{4}}=\frac{18x^{7}}{-2x^{4}}-\frac{9x^{6}}{-2x^{4}}+\frac{20x^{5}}{-2x^{4}}-\frac{10x^{4}}{-2x^{4}}$
= $-9x^{3}+\displaystyle \frac{9}{2}x^{2}-10x+5$
