Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 6 - Section 6.4 - Division of Polynomials - Exercise Set - Page 444: 3


$6x^{2}+2x-3-\displaystyle \frac{2}{x}$

Work Step by Step

Using the property: $\displaystyle \quad\frac{A+B}{C}=\frac{A}{C}+\frac{B}{C},$ $\displaystyle \frac{18x^{3}+6x^{2}-9x-6}{3x}=\frac{18x^{3}}{3x}+\frac{6x^{2}}{3x}-\frac{9x}{3x}-\frac{6}{3x}$ $= 6x^{3-1}+2x^{2-1}-3x^{1-1}-2x^{-1}$ = $6x^{2}+2x-3-\displaystyle \frac{2}{x}$
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