Answer
$5x^{2}+10x-8-\displaystyle \frac{2}{x}$
Work Step by Step
Using the property: $\displaystyle \quad\frac{A+B}{C}=\frac{A}{C}+\frac{B}{C},$
$\displaystyle \frac{25x^{3}+50x^{2}-40x-10}{5x}=\frac{25x^{3}}{5x}+\frac{50x^{2}}{5x}-\frac{40x}{5x}-\frac{10}{5x}$
= $5x^{2}+10x-8-\displaystyle \frac{2}{x}$
