Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 6 - Section 6.4 - Division of Polynomials - Exercise Set - Page 444: 10

Answer

$4ab+2a-5b$

Work Step by Step

Using the property: $\displaystyle \quad\frac{A+B}{C}=\frac{A}{C}+\frac{B}{C},$ $\displaystyle \frac{12a^{2}b^{2}+6a^{2}b-15ab^{2}}{3ab}=\frac{12a^{2}b^{2}}{3ab}+\frac{6a^{2}b}{3ab}-\frac{15ab^{2}}{3ab}$ = $4ab+2a-5b$
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