## Intermediate Algebra for College Students (7th Edition)

$x+3$
$\begin{array}{ccccccccccc} & &x & +3 & & \\ & &--& -- & -- & -- \\ x+5&) &x^{2} &+8x& +15 & \\ & &x^{2} & +5x& & \color{red}{\leftarrow \small{x(x+5) } } \\ \ & &--& -- & & \color{red}{ \small{subtract}} \\ & & & 3x & +15 & \\ & & & 3x & +15 & \color{red}{\leftarrow \small{3(x+5) } } \\ \ & & &--& -- & \color{red}{ \small{subtract}} \\ & & & & 0 & \end{array}$ Quotient is $x+3$, Remainder is $0$. $\displaystyle \frac{dividend}{divisor}=quotient+\frac{remainder}{divisor}$ $\displaystyle \frac{x^{2} +8x +15}{x+5}$ = $x+3$