Answer
$\frac{19x+10y}{(x+y)(x-y)}$
Work Step by Step
$\frac{9x}{x^2-y^2}-\frac{10}{y-x}=\frac{9x}{(x+y)(x-y)}+\frac{10}{x-y}=\frac{9x}{(x+y)(x-y)}+\frac{10(x+y)}{(x-y)(x+y)}=\frac{9x+10x+10y}{(x+y)(x-y)}=\frac{19x+10y}{(x+y)(x-y)}$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 6 - Section 6.2 - Adding and Subtracting Rational Expressions - Exercise Set - Page 427: 56
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