# Line slope calculator 5x+9y=50

**Straight line given by points A[1; 5] and B[10; 0]**

## Calculation:

**Slope-intercept form of line:**y = -0.5556x+5.5556

**Canonical form of the line equation:**5x+9y-50 = 0

**Parametric form of the line equation:**

x = 9t+1

y = -5t+5 ; t ∈ R

**Slope:**m = -0.5556

**Slope angle of line: φ =**-29°3'17″ = -0.5071 rad

**X intercept:**x

_{0}= 10

**Y intercept:**y

_{0}= q = 5.5556

**Distance line from the origin:**d

_{0}= 4.8564

**The length of the segment AB: |AB| =**10.2956

**Vector: AB =**(9; -5)

**Normal vector: n =**(5; 9)

**Midpoint of the segment AB: M =**[5.5; 2.5]

**Perpendicular Bisector equation:**9x-5y-37 = 0

**Vector OA = (1; 5) ; |OA| = 5.099**

**Vector OB = (10; 0) ; |OB| = 10**

**Scalar product OA .OB = 10**

**Angle ∠ AOB = 78°41'24″ = 1.3734 rad**