Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 6 - Section 6.2 - Adding and Subtracting Rational Expressions - Exercise Set - Page 427: 32



Work Step by Step

Clearly LCD$=(x-3)(x+2)$, thus $\frac{2}{x-3}+\frac{7}{x+2}=\frac{2(x+2)+7(x-3)}{(x-3)(x+2)}=\frac{2x+4+7x-21}{(x-3)(x+2)}=\frac{9x-17}{(x-3)(x+2)}$
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