Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 6 - Section 6.2 - Adding and Subtracting Rational Expressions - Exercise Set - Page 427: 31



Work Step by Step

Clearly LCD$=(x-2)(x+1)$, thus $\frac{4}{x-2}+\frac{3}{x+1}=\frac{4(x+1)+3(x-2)}{(x-2)(x+1)}=\frac{4x+4+3x-6}{(x-2)(x+1)}=\frac{7x-2}{(x-2)(x+1)}$
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