Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Cumulative Review Exercises - Page 402: 2



Work Step by Step

Given: $2x+4y=-6$ and $x=2y-5$ Now, $2(2y-5)+4y=-6$ or, $4y-10+4y=-6$ This implies that $4y-10+4y+6=0$ or, $8y-4=0 \implies y=\dfrac{1}{2}$ Thus, $x=2y-5=2(\dfrac{1}{2})-5=-4$ Hence, {$x,y$}$=${$-4,\dfrac{1}{2}$}
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