Chapter 5 - Cumulative Review Exercises - Page 402: 2

{$x,y$}$=${$-4,\dfrac{1}{2}$}

Given: $2x+4y=-6$ and $x=2y-5$ Now, $2(2y-5)+4y=-6$ or, $4y-10+4y=-6$ This implies that $4y-10+4y+6=0$ or, $8y-4=0 \implies y=\dfrac{1}{2}$ Thus, $x=2y-5=2(\dfrac{1}{2})-5=-4$ Hence, {$x,y$}$=${$-4,\dfrac{1}{2}$}