Answer
$(x-3)^2(x+3)$
Work Step by Step
The product of a binomial sum and a binomial difference is: $(A+B)(A-B)=A^2-B^2$.
Hence: $x^3-3x^2-9x+27=\\=x^2(x-3)-9(x-3)\\=(x-3)(x^2-9)\\=(x-3)(x+3)(x-3)\\=(x-3)^2(x+3)$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 5 - Cumulative Review Exercises - Page 402: 18
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