Answer
$\frac{-y^{10}}{2x^{6}}$
Work Step by Step
$\frac{-8x^3y^6}{16x^9y^{-4}}=\frac{-8}{16}x^{3-9}y^{6-(-4)}=\frac{-1}{2}x^{-6}y^{10}=\frac{-y^{10}}{2x^{6}}$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 5 - Cumulative Review Exercises - Page 402: 14
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