Answer
$x^2(x^2+1)(x+1)(x-1)$
Work Step by Step
The product of a binomial sum and a binomial difference is: $(A+B)(A-B)=A^2-B^2$.
Hence: $x^6-x^2=\\=x^2((x^2)^2-1^2)\\=x^2(x^2+1)(x^2-1)\\=x^2(x^2+1)(x+1)(x-1)$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 5 - Cumulative Review Exercises - Page 402: 19
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