Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 3 - Section 3.1 - Systems of Linear Equations in Two Variables - Exercise Set - Page 191: 89

Answer

Intersect at the graph for $(x,y) =(6,2)$, so $y=x-4$ and $y=\dfrac{12-x}{3}$.

Work Step by Step

To solve the given problem we will have to plug the simplest equation into the other equation and then solve for the other variable. As we are given that $x-y=4$ and $x+3y=12$ This gives $x=4$ Now, $x+3y=12$ or, $4+3y=12$ or, $y=2$ Hence, both the equations gives solution and intersect at the graph for $(x,y) =(6,2)$, so $y=x-4$ and $y=\dfrac{12-x}{3}$
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