Answer
Infinitely many solutions with $(x,y)|2x-y-5=0 $ or $(x,y)|10=4x-2y$
Work Step by Step
To solve the given problem we will have to plug the simplest equation into the other equation and then solve for the other variable.
$2x-y-5=0 $ or $10=4x-2y$
Now, $-4x+2y+10=0$
or, $4x-2y=10$
or, $10=10$
or, $0=0$
Hence, the given equation has Infinitely many solutions with $(x,y)|2x-y-5=0 $ or $(x,y)|10=4x-2y$
