Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 3 - Section 3.1 - Systems of Linear Equations in Two Variables - Exercise Set - Page 191: 84

Answer

$(20,17)$

Work Step by Step

To solve the given problem we will have to plug the simplest equation into the other equation and then solve for the other variable. $2(x+y)=3(x+y)-3(1) $ and $3(x+2)-6(4)=2(y+4)$ This gives $x=20$ Now, $3(x+2)-6(4)=2(y+4)$ or, $3x+6-24=2y+8$ or, $60+6-24=2y+8$ or, $y=17$ Hence, the desired result is $(20,17)$
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