Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 3 - Section 3.1 - Systems of Linear Equations in Two Variables - Exercise Set - Page 191: 83



Work Step by Step

To solve the given problem we will have to plug the simplest equation into the other equation and then solve for the other variable. $3(x+2)-2(y+4)=6(3) $ and $2(x+y)=5(x-y)-25$ Now, $y=-1$ or, $2(x+y)=5(x-y)-25$ or, $2x+2y=5x-5y-25$ or, $2x+2y-5x+5y-25$ or, $-3x+7y=-25$ or, $-3x+7(-1)=-25$ or, $x=6$ Hence, the desired result is $(6,-1)$
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