Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 3 - Section 3.1 - Systems of Linear Equations in Two Variables - Exercise Set - Page 191: 79


Infinitely many solutions with $(x,y)|x+2y-3=0 $ or $(x,y)|12=8y+4x$

Work Step by Step

To solve the given problem we will have to plug the simplest equation into the other equation and then solve for the other variable. $x+2y-3=0 $ or $12=8y+4x$ Now, $-4x-8y+12=0 $ or, $4x+8y=12$ or, $12=12$ Hence, the given equation has Infinitely many solutions with $(x,y)|x+2y-3=0 $ or $(x,y)|12=8y+4x$
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