Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 3 - Mid-Chapter Check Point - Page 220: 8

Answer

$\{\left ( 4,-2,3\right )\}$.

Work Step by Step

The given system of equations is $\Rightarrow x-3z= -5$...... (1) $\Rightarrow 2x-y+2z= 16 $...... (2) $\Rightarrow 7x-3y-5z= 19$...... (3) Multiply equation (2) by $-3$ and add to equation (3). $\Rightarrow -3(2x-y+2z)+7x-3y-5z= -3(16)+19$ Apply distributive property. $\Rightarrow -6x+3y-6z+7x-3y-5z= -48+19$ Simplify. $\Rightarrow x-11z= -29$ Multiply the equation by $-1$ $\Rightarrow -1(x-11z)=-1( -29)$ $\Rightarrow -x+11z=29$...... (4). Add equation (1) and equation (4). $\Rightarrow x-3z-x+11z= -5+29$ Simplify. $\Rightarrow 8z= 24$ Divide both sides by $8$. $\Rightarrow \frac{8z}{8}= \frac{24}{8}$ Simplify. $\Rightarrow z=3$ Substitute the value of $z$ into equation (1). $\Rightarrow x-3(3)= -5$ Simplify. $\Rightarrow x-9= -5$ Add $9$ to both sides. $\Rightarrow x-9+9= -5+9$ Simplify. $\Rightarrow x= 4$ Substitute the values of $x$ and $z$ into equation (2). $\Rightarrow 2(4)-y+2(3)= 16 $ Simplify. $\Rightarrow 8-y+6= 16 $ $\Rightarrow -y+14= 16 $ Subtract $14$ from both sides. $\Rightarrow -y+14-14= 16-14 $ Simplify. $\Rightarrow -y= 2 $ $\Rightarrow y= -2 $ The solution set is $\{\left ( x,y,z\right )\}=\{\left ( 4,-2,3\right )\}$.
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