Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 3 - Mid-Chapter Check Point - Page 220: 12

Answer

Number of roses $=6$. Number of carnations $=14$.

Work Step by Step

Let the number of roses $=x$. and the number of carnations $=y$. Total flowers and carnations $=20$. $\Rightarrow x+y=20$...... (1) Cost of $x$ roses $=3x$. Cost of $y$ roses $=1.50y$ Total cost $=\$39$. $\Rightarrow 3x+1.50y=39$......(2) Multiply equation (1) by $-3$. $\Rightarrow -3(x+y)=-3(20)$ Apply distributive peroperty. $\Rightarrow -3x-3y=-60$...... (3) Add equation (2) and (3). $\Rightarrow 3x+1.50y-3x-3y=39-60$ Simplify. $\Rightarrow -1.50y=-21 $ Divide both sides by $-1.50$. $\Rightarrow \frac{-1.50y}{-1.50}=\frac{-21}{-1.50} $ Simplify. $\Rightarrow y=14$. Substitute the value of $14$ into equation (1). $\Rightarrow x+14=20$ Subtract $14$ form both sides. $\Rightarrow x+14-14=20-14$ Simplify. $\Rightarrow x=6$
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