## Intermediate Algebra for College Students (7th Edition)

The solution is $x=-1$ and $y=2$.
The given equations are $x=3y-7$ ... (1) $4x+3y=2$ ... (2) Substitute the value of $x$ from equation (1) to (2). $4(3y-7)+3y=2$ $12y-28+3y=2$ $15y=2+28$ $15y=30$ $y=\frac{30}{15}$ $y=2$ Substitute into equation (1). $x=3(2)-7$ $x=6-7$ $x=-1$