Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 3 - Mid-Chapter Check Point - Page 220: 3

Answer

The solution is $ x=6 $ and $ y=10 $.

Work Step by Step

The given equations are $ \frac{2x}{3}+\frac{y}{5}=6 $ ... (1) $ \frac{x}{6}-\frac{y}{2}=-4 $ ... (2) Multiply equation (1) by $ 5$ and equation (2) by $2 $. $ \frac{10x}{3}+y=30 $ ... (3) $ \frac{x}{3}-y=-8 $ ... (4) Add equation (3) and (4). $ \frac{10x}{3}+\frac{x}{3}=30-8 $ $ \frac{10x+x}{3}=22 $ $ \frac{11x}{3}=22 $ $ x=22\cdot \frac{3}{11} $ $ x=6 $ substitute into equation (4) $ \frac{6}{3}-y=-8 $ $ 2-y=-8 $ $2+8=y $ $ 10=y $
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