Answer
The graph is shown below.
Work Step by Step
The given equation of the line is
$\Rightarrow f(x)=-\frac{1}{3}x+2$
let $f(x)=y$.
$\Rightarrow y=-\frac{1}{3}x+2$
Plug $y=0$ for the $x−$intercept.
$\Rightarrow 0=-\frac{1}{3}x+2$
Add $\frac{1}{3}x$ to both sides.
$\Rightarrow 0+\frac{1}{3}x=-\frac{1}{3}x+2+\frac{1}{3}x$
Simplify.
$\Rightarrow \frac{1}{3}x=2$
Multiply both sides by $3$.
$\Rightarrow 3\cdot \frac{1}{3}x=3\cdot2$
Simplify.
$\Rightarrow x=6$
The $x−$intercept is $6$, so the line passes through $(6,0)$.
Plug $x=0$ for the $y−$intercept.
$\Rightarrow y=-\frac{1}{3}(0)+2$
Simplify.
$\Rightarrow y=2$
The $y−$intercept is $2$, so the line passes through $(0,2)$.
Checkpoint plug $x=3$.
$\Rightarrow y=-\frac{1}{3}(3)+2$
Simplify.
$\Rightarrow y=-1+2$
$\Rightarrow y=1$
The checkpoint is $(3,1)$.
Draw a straight line through these three points.
