Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 2 - Test - Page 175: 14

Answer

See below.

Work Step by Step

$(f-g)(x)=f(x)-g(x)$ $(f-g)(x)=f(x)-g(x)=x^2+4x-x-2=x^2+3x-2$ Plug in $x=-1$ into $(f-g)(x)$: $(f-g)(-1)=(-1)^2+3(-1)-2=1-3-2=-4$
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