Answer
$(-\infty,-2)\cup(-2,+\infty)$
Work Step by Step
$\frac{f}{g}(x)=\frac{x^2+4x}{x+2}$ Since the denominator can't be equal to 0 $x\ne-2$
The domain is $(-\infty,-2)\cup(-2,+\infty)$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 2 - Test - Page 175: 17
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