Answer
point slope form $y+3=1(x+2)$
slope intercept form $y=x-2$
Work Step by Step
The slope of line is $m=\frac{y_{2}-y_{1}}{x_(2)-x_(1)}=\frac{2-(-3)}{4-(-1)}=\frac{5}{5}=1$
The point slope form is the following $(y-y_2)=m(x-x_2)$ plugging in the known values we have $y+3=1(x+2)$
The slope intercept form is the following $y=mx+b$ where $b=y_2-mx_2=-3-(1)*(-1)=-2$ plugging in the known values we have $y=x-2$
