Answer
The graph is shown below.
Work Step by Step
The given equation of the line is
$\Rightarrow 4x-3y=12$
Plug $y=0$ for the $x−$intercept.
$\Rightarrow 4x-3(0)=12$
Simplify.
$\Rightarrow 4x=12$
Divide both sides by $4$.
$\Rightarrow \frac{4x}{4}=\frac{12}{4}$
Simplify.
$\Rightarrow x=3$
The $x−$intercept is $3$, so the line passes through $(3,0)$.
Plug $x=0$ for the $y−$intercept.
$\Rightarrow 4(0)-3y=12$
Simplify.
$\Rightarrow -3y=12$
Divide both sides by $-3$.
$\Rightarrow \frac{-3y}{-3}=\frac{12}{-3}$
Simplify.
$\Rightarrow y=-4$
The $y−$intercept is $-4$, so the line passes through $(0,-4)$.
Checkpoint plug $x=6$.
$\Rightarrow 4(6)-3y=12$
Simplify.
$\Rightarrow 24-3y=12$
Subtract $24$ from both sides.
$\Rightarrow 24-3y-24=12-24$
Simplify.
$\Rightarrow -3y=-12$
Divide both sides by $-3$.
$\Rightarrow \frac{-3y}{-3}=\frac{-12}{-3}$
$\Rightarrow y=4$
The checkpoint is $(6,4)$.
Draw a straight line through these three points.
