Answer
The answer is $(-\infty,\frac{2}{3})$.
Work Step by Step
The given inequality is
$3x+2<4$ and $4-x>1$
Isolate $x$
$3x+2-2<4-2$ and $4-x-4>1-4$
$3x<2$ and $-x>-3$
In the first inequality divide by $3$ and for the second inequality multiply by $-1$ and change the sign.
$x
