## Intermediate Algebra for College Students (7th Edition)

The dimensions are Length $=8 \; feet$ Width $=3 \; feet$
Let the length is $l$. and the width is $w$. length is 2 feet more than twice its width. In the equation form $l=2w+2$ ... (1) The perimeter of the garden is $P=2(l+w)$ ... (2) In the question we have perimeter equal to length of fencing. $P=22 \; feet$ Plug into equation 2 $22=2(l+w)$ Plug the value of $l$ from equation (1). $22=2(2w+2+w)$ Divide both sides by $2$. $11=3w+2$ Isolate $w$. $w=\frac{11-2}{3}$ $w=\frac{9}{3}$ $w=3$ plug into equation (1). $l=2(3)+2$ $l=6+2$ $l=8$.