Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 11 - Cumulative Review Exercises - Page 872: 23


The answer is $p=\frac{fq}{q-f}$.

Work Step by Step

The given expression is $\frac{1}{p}+\frac{1}{q}=\frac{1}{f}$ Subtract $\frac{1}{q}$ from both sides. $\frac{1}{p}+\frac{1}{q}-\frac{1}{q}=\frac{1}{f}-\frac{1}{q}$ Simplify. $\frac{1}{p}=\frac{1}{f}-\frac{1}{q}$ Subtract on the right hand side. $\frac{1}{p}=\frac{q-f}{fq}$ Reciprocate both sides. $\frac{p}{1}=\frac{fq}{q-f}$ $p=\frac{fq}{q-f}$.
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