## Intermediate Algebra for College Students (7th Edition)

The answer is $p=\frac{fq}{q-f}$.
The given expression is $\frac{1}{p}+\frac{1}{q}=\frac{1}{f}$ Subtract $\frac{1}{q}$ from both sides. $\frac{1}{p}+\frac{1}{q}-\frac{1}{q}=\frac{1}{f}-\frac{1}{q}$ Simplify. $\frac{1}{p}=\frac{1}{f}-\frac{1}{q}$ Subtract on the right hand side. $\frac{1}{p}=\frac{q-f}{fq}$ Reciprocate both sides. $\frac{p}{1}=\frac{fq}{q-f}$ $p=\frac{fq}{q-f}$.