Answer
The answer is $\frac{5\sqrt[3] {4xy^2}}{2xy}$.
Work Step by Step
The given expression is
$\frac{5}{\sqrt[3] {2x^2y}}$
To rationalize the denominator we multiply and divide by $\sqrt[3] {2^2xy^2}$
$\frac{5}{\sqrt[3] {2x^2y}} \cdot \frac{\sqrt[3] {2^2xy^2}}{\sqrt[3] {2^2xy^2}}$
Simplify.
$\frac{5\sqrt[3] {2^2xy^2}}{2xy}$.
$\frac{5\sqrt[3] {4xy^2}}{2xy}$.
