Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 10 - Section 10.5 - Systems of Nonlinear Equations in Two Variables - Exercise Set - Page 810: 7



Work Step by Step

Re-write the second equation as: $x=y+1$ First equation yield: $(y+1)^2+y^2=25$ or, $y^2+y-12=0$ or, $(y+4)(y-3)=0$ or, $y=${$-4,3$} From first equation when $y=-4$, we have $x=-3$ From first equation when $y=3$, we have $x=4$ Thus, solution set is $(x,y)=${$(-3,-4),(4,3)$}
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