Chapter 10 - Section 10.5 - Systems of Nonlinear Equations in Two Variables - Exercise Set - Page 810: 35

{$(-1,1),(0,0)$}

After adding the two equations, we get $x^3+x^2=0$ or, $x^2(x+1)=0$; or $x=${$-1,0$} From first equation $x^3+y=0$ when $x=-1$, we have $y=1$ From first equation $x^3+y=0$ when $x=0$, we have $y=0$ Thus, solution set is: {$(-1,1),(0,0)$}