Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 10 - Section 10.5 - Systems of Nonlinear Equations in Two Variables - Exercise Set - Page 810: 6



Work Step by Step

From the first and second equations, we have $x^2+4x+5=x^2+2x-1$ or, $2x=-6$ or, $x=-3$ From first equation when $x=-3$, we have $y=(-3)^2+4(-3)+5=9-12+5=2$ Thus, solution set is $(x,y)=${$(-3,2)$}
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