Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 10 - Section 10.5 - Systems of Nonlinear Equations in Two Variables - Exercise Set - Page 810: 20



Work Step by Step

After adding the given two equations, we get $8x^2=8$ or, $x^2=1$; or $x=\pm 1$ From first equation $4x^2-y^2=4$ when $x=1$, we have $y=0$ From first equation $4x^2-y^2=4$ when $x=-1$, we have $y=0$ Thus, solution set is {$(1,0),(-1,0)$}
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