Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 10 - Section 10.5 - Systems of Nonlinear Equations in Two Variables - Exercise Set - Page 810: 36

Answer

{$(-2,8),(0,0)$}

Work Step by Step

After adding the two equations, we get $x^3+2x^2=0$ or, $x^2(x+2)=0$; or $x=${$-2,0$} From first equation $x^3+y=0$ when $x=-2$, we have $y=8$ From first equation $x^3+y=0$ when $x=0$, we have $y=0$ Thus, solution set is: {$(-2,8),(0,0)$}
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