Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Section 1.6 - Properties of Integral Exponents - Exercise Set: 89

Answer

$\dfrac{2}{x^7}$

Work Step by Step

RECALL: (i) $\dfrac{a^m}{a^n} = a^{m-n}, a \ne 0$ (ii) $a^{-m} = \dfrac{1}{a^m}, a\ne0$ Divide the coefficients by each other and the variables by each other to obtain: $=\dfrac{16}{8} \cdot x^{3-10} =2 \cdot x^{-7}$ Use rule (ii) above to obtain: $=2 \cdot \dfrac{1}{x^7} \\=\dfrac{2}{x^7}$
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