## Intermediate Algebra for College Students (7th Edition)

Published by Pearson

# Chapter 1 - Section 1.6 - Properties of Integral Exponents - Exercise Set - Page 80: 111

#### Answer

$1$

#### Work Step by Step

RECALL: For any non-zero real number $x$, $x^0=1$ Use the rule above to obtain: $\left(\dfrac{3a^{-5}b^2}{12a^3b^{-4}}\right)^0=1$

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