## Intermediate Algebra for College Students (7th Edition)

$-\frac{4}{x}$
$\frac{20x^3}{-5x^4}$ Apply the fraction rule: $\frac{a}{-b} = -\frac{a}{b}$ Hence, $\frac{20x^3}{-5x^4}$ = $-\frac{20x^3}{5x^4}$ $=-\frac{4x^3}{x^4}$ Recall that $\frac{a^m}{a^n} = \frac{1}{a^{n-m}}$ Thus, $-\frac{4x^3}{x^4}= -\frac{4}{x^{4-3}}$ $=-\frac{4}{x}$