## Intermediate Algebra for College Students (7th Edition)

$-\dfrac{32x^5}{y^5}$
The given expression can be written as: $=\left(\dfrac{-2x}{y}\right)^5$ (i) The quotients-to-powers rule states that: $(\frac{a}{b})^n=\frac{a^n}{b^n}$ (ii) The products-to-powers rule states that: $(xy)^n = x^ny^n$ Use the quotients-to-powers rule to find: $=\dfrac{(-2x)^5}{y^5}$ Use the product-to-powers rule to find: $\\=\dfrac{(-2)^5x^5}{y^5} \\=\dfrac{-32x^5}{y^5} \\=-\dfrac{32x^5}{y^5}$