Answer
$\dfrac{-5}{x}$
Work Step by Step
RECALL:
(i) $\dfrac{a^m}{a^n} = a^{m-n}, a \ne 0$
(ii) $a^{-m} = \dfrac{1}{a^m}, a\ne0$
Divide the coefficients by each other and the variables by each other to obtain:
$=\dfrac{10}{-2} \cdot x^{5-6}
=-5 \cdot x^{-1}$
Use rule (ii) above to obtain:
$=-5 \cdot \dfrac{1}{x^1}
\\=\dfrac{-5}{x}$
