## Intermediate Algebra for College Students (7th Edition)

$\dfrac{-5}{x}$
RECALL: (i) $\dfrac{a^m}{a^n} = a^{m-n}, a \ne 0$ (ii) $a^{-m} = \dfrac{1}{a^m}, a\ne0$ Divide the coefficients by each other and the variables by each other to obtain: $=\dfrac{10}{-2} \cdot x^{5-6} =-5 \cdot x^{-1}$ Use rule (ii) above to obtain: $=-5 \cdot \dfrac{1}{x^1} \\=\dfrac{-5}{x}$