## Intermediate Algebra for College Students (7th Edition)

$-5$
First, solving for x, $13x-6=4(5x+2)$ $13x-6=20x+8$ $7x=-14$ $x=-2$ Second, solving for y, $5-y=7(y+4)+1$ $5-y=7y+28+1$ $8y=-24$ $y=-3$ Now, inserting the values of x and y, $x^{2}-(xy-y)=(-2)^{2}-((-2)(-3)-(-3))=4-(6+3)=-5$