## Intermediate Algebra for College Students (7th Edition)

Published by Pearson

# Chapter 1 - Section 1.4 - Solving Linear Equations - Exercise Set: 48

identity

#### Work Step by Step

Distribute $-3$ on the left side and 6 on the right side then combine like terms on each side to obtain: $3x-3(2) -3(-x)=6(x) -6(1) \\3x - 6 -(-3x)=6x-6 \\3x-6+3x=6x-6 \\6x-6=6x-6$ Subtract $6x$ and add $6$ on both sides of the equation to obtain: $6x-6x=-6+6 \\0=0$ The statement above is true therefore the given equation is an identity.

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