# Chapter 1 - Section 1.4 - Solving Linear Equations - Exercise Set - Page 51: 49

conditional equation

#### Work Step by Step

Distribute $3$ on the left side and $6$ on the right side then combine like terms on each side to obtain: $y+3(4y)+3(2) = 6(y) + 6(1) + 5y \\y+12y+6=6y+6+5y \\13y+6=11y+6$ Subtract $11y$ and $6$ on both sides of the equation to obtain: $13y-11y=6-6 \\2y=0 \\y=0$ The given equation has one solution therefore it is a conditional equation.

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