#### Answer

conditional equation

#### Work Step by Step

Distribute $3$ on the left side and $6$ on the right side then combine like terms on each side to obtain:
$y+3(4y)+3(2) = 6(y) + 6(1) + 5y
\\y+12y+6=6y+6+5y
\\13y+6=11y+6$
Subtract $11y$ and $6$ on both sides of the equation to obtain:
$13y-11y=6-6
\\2y=0
\\y=0$
The given equation has one solution therefore it is a conditional equation.