Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Section 1.4 - Solving Linear Equations - Exercise Set - Page 51: 57



Work Step by Step

First, solving for x, $3(x+3)=5(2x+6)$ $3x+9=10x+30$ $7x=-21$ $So,\,\,\,x=-3$ Second, solving for y, $-2y-10=5y+18$ $7y=-28$ $So,\,\,\,y=-4$ Now, inserting values of x and y, $x^{2}-(xy-y)=(-3)^{2}-((-3)(-4)-(-4))=9-(12+4)=-7$
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